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0.15x^2+0.95x+1=0
a = 0.15; b = 0.95; c = +1;
Δ = b2-4ac
Δ = 0.952-4·0.15·1
Δ = 0.3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.95)-\sqrt{0.3025}}{2*0.15}=\frac{-0.95-\sqrt{0.3025}}{0.3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.95)+\sqrt{0.3025}}{2*0.15}=\frac{-0.95+\sqrt{0.3025}}{0.3} $
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